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21 August, 01:57

How much heat is released when 85.0 grams of liquid water freezes to ice, at 0 degrees celcius

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  1. 21 August, 05:19
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    To calculate the amount of heat entering or leaving a system, the equation Q=mcΔT is used.

    Explanation:

    m = mass (in grams)

    c = specific heat capacity (J/g°C)

    ΔT = change in temperature (°C)

    Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

    The mass given is 25.0 grams.

    As for the change in temperature, I will assume that it start off at room temperature, 25°C.

    25°C-0°C=25°C

    Q=mcΔT

    Q=25grams⋅4.19 J g°C ⋅25°C

    Q=2618.75J

    Take into account significant figures and the answer should be

    2.6⋅ 103 J
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