What pressure (in atm) will 0.44 moles of co2 exert in a 2.6 l container at 25°c?

We can use the ideal gas law equation to find the pressure

PV = nRTwhere

P - pressure

V - volume - 2.6 x 10⁻³ m³

n - number of moles - 0.44 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - temperature - 25 °C + 273 = 298 K

substituting the values into the equation,

P x 2.6 x 10⁻³ m³ = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K

P = 419 281.41 Pa

101 325 Pa is equivalent to 1 atm

Therefore 419 281.41 Pa - 1 / 101 325 x 419 281.41 = 4.13 atm

Pressure is 4.13 atm