What is the [oh-] of a solution if its ph = 8.78? answer in units of m?

Question

Chemistry

Emmalee Marquez

20 August, 17:53

What is the [oh-] of a solution if its ph = 8.78? answer in units of m?

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Answers (1)

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Salma Morrison · Answer 1

PH = - log ([H+])

[H+] = 10^ (-pH)

[H+] = 10^ (-8.78) = 1.65*10^-9

[H+][OH-] = Kw

Kw = 1.0*10^-14 at 25 degrees celsius.

[OH-] = Kw/[H+] = (1.0*10^-14) / (1.65*10^-9) = 6.06*10^-6

The concentration of OH - ions is 6.1*10^-6 M.