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18 November, 07:05

Determine the Celsius temperature of 2.08 moles of gas contained in a 1.00 L vessel at a pressure of 177 kPa. - 183 Incorrect: Your answer is incorrect. °C

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  1. 18 November, 09:45
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    We can use the ideal gas law equation to find the temperature,

    PV = nRT

    where

    P - pressure - 177 kPa

    V - volume 1.00 x 10⁻³ m³

    n - number of moles - 2.08 mol

    R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

    T - temperature

    substituting these values in the equation

    177 x 10³ Pa x 1.00 x 10⁻³ m³ = 2.08 mol x 8.314 Jmol⁻¹K⁻¹ x T

    T = 10.2 K

    temperature in celsius - 10.2 - 273 = - 262.8 °C
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