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27 January, 15:33

An upright cylindrical tank with radius 6 m is being filled with water at a rate of 2 m3/min. how fast is the height of the water increasing? if h is the water's height, the volume of the water is v = πr2h. we must find dv/dt. differentiating both sides of the equation gives

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  1. 27 January, 16:09
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    Volume = pir^2h = 36pih Derivative = 36pi dh/dt v' = 2 m^3/min 2 = 36pi dh/dt dh/dt = 0.0177 m/min.
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