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2 July, 11:35

If you start with 56.0 grams of sodium, how many moles of water will react with it?

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  1. 2 July, 13:09
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    Answer is: 2.43 mol of water.

    Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

    m (Na) = 56 g.

    n (Na) = m (Na) : M (Na).

    n (Na) = 56 g : 23 g/mol.

    n (Na) = 2.43 mol.

    From chemical reaction: n (Na) : n (H₂O) = 2 : 2 (1 : 1).

    n (H₂O) = 2.43 mol.

    m (H₂O) = 2.43 mol · 18 g/mol.

    m (H₂O) = 43.82 g.
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