2h3po4 + 3mg (oh) 2 → mg3 (po4) 2 + 6h2o phosphoric acid, h3po4, is neutralized by magnesium hydroxide, mg (oh) 2, according to the equation shown. how many moles of water will be produced from the neutralization of 0.24 mole of h3po4? 0.72 mol 0.48 mol 0.24 mol 1.44 mol

The balanced equation for the neutralisation reaction is as follows

2H₃PO₄ + 3Mg (OH) ₂ - - > Mg₃ (PO₄) ₂ + 6H₂O

stoichiometry of H₃PO₄ to H₂O is 2:6

number of H₃PO₄ moles reacted - 0.24 mol

if 2 mol of H₃PO₄ form 6 mol of H₂O

then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O

therefore 0.72 mol of H₂O are formed