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23 August, 20:25

How many grams of ca are needed to react completely with 2.20 L of a 4.50 m hcl solution

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  1. 23 August, 23:34
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    Ca + 2HCl = CaCl₂ + H₂

    c=4.50 mol/l

    v=2.20 l

    n (HCl) = cv

    m (Ca) / M (Ca) = n (HCl) / 2

    m (Ca) = M (Ca) cv/2

    m (Ca) = 40g/mol·4.50mol/l·2.20l/2=198 g

    198 grams of Ca are needed
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