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22 October, 09:34

A gas has a temperature of 273.15 k and a pressure of 101.325 kpa. what can be concluded about the gas?

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  1. 22 October, 10:26
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    We are given with a temperature of 273.15 Kelvin and a pressure of 101.325 kPa. Using PV=nRT rule of ideal gas, where P is pressure, V is volume, n is the number of moles, R is the gas constant and T is temperature, we can conclude that the conditions are under STP (standard temp and pressure) and one mole of this gas occupies 22.4 L of volume.
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