How many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double displacement reaction?

Balanced equation:

CaO + 2 HCl - - > CaCl2 + H2O

Calculate moles of each reactant:

60.4 g CaO / 56.08 g/mol = 1.08 mol CaO

69.0 g HCl / 36.46 g/mol = 1.89 mol HCl

Identify the limiting reactant:

Moles CaO needed to react with all HCl:

1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO

Because you have more CaO than that available, HCl is the limiting reactant.

Calculate moles and mass CaCl2:

1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2