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11 December, 10:43

For the following metal and non-metal combination reaction you have 3 moles of Na. How many moles of Cl2 would you need to add to have stoichiometrically equivalent amounts of NA and Cl2?

2Na (s) + Cl2 (g) - - > 2NaCl (s)

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  1. 11 December, 11:59
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    The molar ratio of Na : Cl₂ is 2:1

    Moles of Na present = 3

    2/1 = 3/x

    x = 1.5

    1.5 moles of Cl₂ needed to have stoichometrically equivalent amount
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