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22 April, 20:49

How many atoms of carbon are in 0.425 g of ibuprofen?

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  1. 22 April, 23:22
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    Answer is: 1,6·10²².

    Molecular formula of ibuprofen is C₁₃H₁₈O₂.

    m (C₁₃H₁₈O₂) = 0,425 g.

    n (C₁₃H₁₈O₂) = m (C₁₃H₁₈O₂) : m (C₁₃H₁₈O₂)

    n (C₁₃H₁₈O₂) = 0,425g : 206,3 g/mol = 0,002mol.

    n (C) : n (C₁₃H₁₈O₂) = 13 : 1

    n (C) = 0,026 mol.

    N (C) = n (C) · Na = 0,026 mol · 6·10²³ 1/mol = 1,6·10²².

    Na - Avogadro number.
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