The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

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Chemistry

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18 December, 12:03

The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?

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Demetrius · Answer 1

The ionization equation is:

HF ⇄ H (+) + F (-)

The ionization constant is Ka = [H (+) ] * [H (-) ] / [HF]

=> [H (+) ] * [F (-) ] = Ka * [HF]

Given that Ka < 1

[H (+) ] * [F (-) ] < [HF]

Which is [HF] > [H (+) ] * [F (-) ] the option a. fo the list of choices.