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27 December, 00:58

For the hypothetical reactions 1 and 2, k1 = 102 and k2 = 10-4. 1. a2 (g) + b2 (g) 2ab (g) 2. 2a2 (g) + c2 (g) 2a2c (g) 3. a2c (g) + b2 (g) 2ab (g) + (1/2) c2 (g) what is the value for k for reaction 3?

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  1. 27 December, 03:52
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    Answer is: valeu for K is 10⁴.

    Reaction 1: A₂ + B₂ → 2AB.

    Reaction 2: 2A₂ + C₂→ 2A₂C.

    Reaction 3: A₂C + B₂ → 2AB + 1/2C.

    Reaction 3 is reaction 1 + 1/2 reverse reaction 2.

    K₁ = 10².

    K₂ = 10⁻⁴.

    K₃ = 10² · √10⁴ = 10² · 10² = 10⁴.
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