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28 November, 15:29

This solution contains equal concentrations of both hf (aq) and naf (aq). write the proton transfer equilibrium (net ionic) reaction that includes f - as a reactant. include states of matter.

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  1. 28 November, 17:22
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    We are asked to provide the net ionic equation for the reaction of HF (aq) and NaF (aq). HF is a weak acid and is in the following equilibrium:

    HF (aq) ⇄ H⁺ (aq) + F⁻ (aq)

    Meanwhile, NaF (aq) is an ionic compound that will dissociate completely in aqueous solutions:

    NaF (aq) → Na⁺ (aq) + F⁻ (aq)

    We can combine the ionic species with HF, as we are told to show F⁻ as a reactant:

    HF (aq) + Na⁺ (aq) + F⁻ (aq) → HF (aq) + Na⁺ (aq) + F⁻ (aq)

    We can eliminate the spectator ions, which in this case are Na⁺ ions, and this leaves us with the net ionic equation involving F⁻:

    HF (aq) + F⁻ (aq) → HF (aq) + F⁻ (aq)

    In this instance, the proton is just transferred between F⁻ ions and the end result is the formation of more HF, so there is no net reaction taking place.
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