What is the concentration of iron ions (in M) in a 7.08 M solution of Fe3 (PO4) 2

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Chemistry

Mareli Camacho

2 December, 11:19

What is the concentration of iron ions (in M) in a 7.08 M solution of Fe3 (PO4) 2

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Brogan · Answer 1

21.2 M

Fe3 (PO4) 2 when dissolved breaks up into 5 ions. 3 Fe ions, and 2 PO4 ions. So for every mole of Fe3 (PO4) 2 in the solution, there are 3 moles of Fe ions created. Therefore 3 * 7.08 M = 21.24M which to 3 significant figures is 21.2 M