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14 November, 06:29

What volume of 18 m sulfuric acid must be used to prepare 1.80 l of 0.215 m h2so4?

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  1. 14 November, 09:14
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    The rule that we will use to solve this question is:

    (M*V) 1 = (M*V) 2 where:

    M is the molarity and V is the volume

    We are given that:

    M1 = 18 m

    M2 = 0.125 m

    V2 = 1.8 l

    we need to find V1

    So, we will just substitute in the above equation to get V1 as follows:

    18 (V1) = 0.125 (1.8)

    V1 = 0.0125 liters
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