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28 September, 00:28

A. 35 m solution of weak acid, HX, has a h + of 4.15*10^-3. what is the value of ka for this acid

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  1. 28 September, 00:48
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    Ka has the formula:

    Ka = [H+] [X-] / [HX]

    We have the following given:

    [H+] = 4.15x10^-3

    [HX] = 0.35

    Since the acid dissociates in a ratio of 1 [H+] to 1 X,

    [H+] = [X-]

    Plugging in the values,

    Ka = (4.15x10^-3) (4.15x10-3) / 0.35

    Ka = 4.92x10^-5
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