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24 September, 09:25

Describe, in detail, how to make 3.0 liters of a 3.5 molar HCl solution from an 18.5 molar HCl stock solution

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  1. 24 September, 12:38
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    C1V1=C2V2,

    where C is concentration and V is volume,

    so let say C1=18.5M, V1=?,

    C2=3.5M, V2=3.0L,

    now solve for V1, in this case V1=0.57L, so in order to make a 3.0L solution we will need to take 0.57L of stock HCl and add 2.43L of water.
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