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20 February, 03:17

Theoretically how many moles of carbonic acid will be produced by the 3.00 g sample of NaHCO3

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  1. 20 February, 03:57
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    NaHCO3 = 22.99 + 1.008 + 16 (3) = 83.99 g/mol

    Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27%

    3.0 g *.2727 = 0.8211 grams of sodium in sample of NaHCO3

    0.8211 grams Na + 1.266 grams Cl = 2.087 grams
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