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15 March, 19:23

Here is the discharge reaction for an alkaline battery: zn (s) + 2mno2 (s) + h2o (l) / longrightarrow⟶⟶zn (oh) 2 (s) + mn2o3 (s) which species is reduced as the battery is discharged?

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  1. 15 March, 20:36
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    The reaction is

    Zn (s) + 2MnO₂ (s) + H₂O (l) ⟶ Zn (OH) ₂ (s) + Mn₂O₃ (s)

    The reactants are Zn (s) and MnO₂ (s) while Zn (OH) ₂ (s) and Mn₂O₃ (s) products.

    Let's see the oxidation state of each compound.

    sum of the o. s. of the each element of compound = charge of the compound

    O. s of O = - 2

    O. s of OH⁻ = - 1

    O. s of Zn (s) = 0

    O. s of Mn in MnO₂ (s) = x

    x + (-2) * 2 = 0

    x = + 4

    O. s of Zn in Zn (OH) ₂ (s) = a

    a + (-1) * 2 = 0

    a = + 2

    O. s of Mn in Mn₂O₃ (s) = b

    2*b + (-2) * 3 = b

    2b = 6

    b = + 3

    Since the O. s is reduced in Mn from + 4 to + 3, the reduced species is Mn₂O₃ (s).
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