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23 January, 11:55

Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of Pb (NO3) 2 are heated to give 5.5 g of PbO? 2Pb (NO3) 2 (s) → 2PbO (s) + 4NO2 (

g. + O2 (

g.

0
Answers (1)
  1. 23 January, 13:04
    0
    2Pb (NO₃) ₂ = 2PbO + 4NO₂ + O₂

    m{Pb (NO₃) ₂}=9.9 g

    m'{PbO}=5.5 g

    M{Pb (NO₃) ₂}=331.2 g/mol

    M{PbO}=223.2 g/mol

    w-?

    w=m'{PbO}/m{PbO}

    m{PbO}=M{PbO}m{Pb (NO₃) ₂}/M{Pb (NO₃) ₂}

    w=m'{PbO}M{Pb (NO₃) ₂}/[M{PbO}m{Pb (NO₃) ₂}]

    w=5.5*331.2/[223.2*9.9]=0.8244 (82.44%)
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