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18 August, 13:51

Calculate the PH of 0.25mol H2SO4

Ka = 1.9 x 10-5

only have experience with simpler ones like KOH, the H2SO4 is whats confusing me

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  1. 18 August, 14:52
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    This problem uses the relationship between Ka and the concentrations of the ions. Calculations are as follows:

    1.9 x 10-5 = x^2 / (0.25 - x)

    x is very small and the denominator is approximately equal to 0.25. Thus, x is 2.2 x 10^-3

    pH = - log (2.2 x 10^-3) = 2.66
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