Part a in an effusion experiment, it was determined that nitrogen gas, n2, effused at a rate 1.812 times faster than an unknown gas. what is the molar mass of the unknown gas? express your answer to four significant figures and include the appropriate units.

Question

Chemistry

Clay Mccullough

24 August, 11:18

Part a in an effusion experiment, it was determined that nitrogen gas, n2, effused at a rate 1.812 times faster than an unknown gas. what is the molar mass of the unknown gas? express your answer to four significant figures and include the appropriate units.

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Answers (1)

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Ali Hunt · Answer 1

Effusion rate, R, is inversely proportional to the square root of the molar mass, M:

R α 1 / √M

Let Ra be the effusion rate of a gas with molar mass Ma and Rb the efussion rate of a gas with molar mass Mb, then:

Ra / Rb = √ [Mb / Ma]

You know Ra / Rb = 1.82 and Ma = molar mass of N2 = 28.02 g/mol

=> Mb = [Ra / Rb]^2 * Ma = (1.82) ^2 * 28.02 g/mol = 92.81 g/mol

Answer: 92.81 g/mol