2H2O2 (aq) - - > O2 (g) + 2H2O (l). If you use 0.20 M of KI instead of 0.10 M of KI, How would this affect: (a) the slopes of your curves, (b) the rates of the reactions, and (c) the numerical value of k for the reaction?

Question

Chemistry

Uriah Harmon

20 July, 14:32

2H2O2 (aq) - - > O2 (g) + 2H2O (l). If you use 0.20 M of KI instead of 0.10 M of KI, How would this affect: (a) the slopes of your curves, (b) the rates of the reactions, and (c) the numerical value of k for the reaction?

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Uriel · Answer 1

This very much depends on order in respect to KI

order of Zero, no change, order 1, rate doubles, order 2, rate quadruples. Which is also one way of working out the rate order.

no change onto steeper on curves. (0 thro ...)

k shouldn't change.

Best Answer is (c) the numerical value of k for the reaction