Suppose that you have made a saturated solution of this solute using 56.0 g of water at 20.0 °c. how much more solute can you add if the temperature is increased to 30.0 °c?

Mass of water = 56 grams.

So at 20 degrees, Solubility of water = 37.4 g in 100g

Solute = 56 x (37.4 / 100) = 20.944

So at 30 degrees, Solubility of water = 71.5 g in 100g

Solute = 56 x (71.5 / 100) = 40.04

So with the increase of temperature increase in solute = 40.04 - 20.944 = 19

.096 grams