Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her calculations, s/he mistakenly uses 85.237 g ± 0.005 g for massA. S/he uses the correct values for massB and masscyl. Will the calculated mass of displaced water be too high, too low, or unchanged? And why?

Question

Chemistry

Bruce Patterson

21 January, 17:44

Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her calculations, s/he mistakenly uses 85.237 g ± 0.005 g for massA. S/he uses the correct values for massB and masscyl. Will the calculated mass of displaced water be too high, too low, or unchanged? And why?

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Answers (2)

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Elias · Answer 1

It is going to be too low because the mass mistakenly used is lower than the initial.

Jayvion Holmes · Answer 2

Answer: - Calculated mass of displaced water would be too low.

Explanations: - Mass of water displaced is directly proportional to the mass of the object dropped into water.

Since the average mass of A used for calculations is low than the actual mass, the calculated mass of displaced water would also be low.