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20 October, 01:51

Determine the molarity of a solution made by dissolving 11.7 g of NaNO3 in water where the final volume of the solution is 250.0 mL.

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  1. 20 October, 05:04
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    Molarity is defined as the number of moles of solute in 1 L solution.

    we have been given the mass of NaNO₃ dissolved in 250.0 mL

    number of moles of NaNO₃ - 11.7 g / 85 g/mol = 0.138 mol

    number of NaNO₃ moles in 250.0 mL - 0.138 mol

    since molarity is the number of moles in 1 L

    number of NaNO₃ moles in 1000 mL - 0.138 mol / 250.0 mL x 1000mL/L = 0.552 mol

    molarity of NaNO₃ is 0.552 M
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