A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this reaction? caco3 (s) ⟶ cao (s) + co2 (s)

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Chemistry

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1 November, 15:42

A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this reaction? caco3 (s) ⟶ cao (s) + co2 (s)

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Bo Sloan · Answer 1

CaCO3 (s) ⟶ CaO (s) + CO2 (s)

moles CaCO3: 1.31 g/100 g/mole CaCO3 = 0.0131

From stoichiometry, 1 mole of CO2 is formed per 1 mole CaCO3, therefore 0.0131 moles CO2 should also be formed.

0.0131 moles CO2 x 44 g/mole CO2 = 0.576 g CO2

Therefore:

% Yield: 0.53/.576 x100 = 92 percent yield