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21 February, 07:11

show me the steps for solving this problem

how many grams of O2 are required to burn 46.0 grams of C5H12

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  1. 21 February, 09:25
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    (MM) C5H12=5x12+12x1=72g/mol

    (MM) O2=2x16=32g/mol

    Acoording to equation:

    C5H12 + 8O2 = > 5CO2 + 6H2O

    The proportion between C5H12 and O2 is 1:8 in mol

    So: 72/16=46/x finale x=10,2g of O2
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