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24 January, 02:33

How many atoms are present in 0.10mol of ptcl2 (nh3) 2?

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  1. 24 January, 02:39
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    The number of atoms present in 0.10 mol of PtCl2 (NH3) is calculated using Avogadro law formula

    that is

    1 mole = 6.02 x10^23 atoms

    what about 0.10 moles = ? atoms

    = 6 ... 02 x10 ^23 x 0.1 = 6.02 x10^22 atoms
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