Ask Question
7 October, 06:08

Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50

+2
Answers (2)
  1. 7 October, 07:21
    0
    NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions.

    Therefore [NaOH] = [OH⁻]

    To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.

    pH + pOH = 14

    Since pH = 11.50

    pOH = 14 - 11.50

    pOH = 2.50

    We can calculate [OH⁻] by knowing pOH

    pOH = - log[OH⁻]

    [OH⁻] = antilog (-pOH)

    [OH⁻] = 3.2 x 10⁻³ M

    therefore [NaOH] = 3.2 x 10⁻³ M
  2. 7 October, 09:07
    0
    We know that;

    pH + pOH = 14

    Thus; pOH = 14-11.5

    = 2.5

    But; pOH = - log [OH-]

    -log[OH} = 2.5

    [OH] = 10 ^-2.5

    = 3.162 x 10^-3 M

    thus; [NaOH] = 3.162 x 10^-3 M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50 ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers