Ask Question
2 September, 14:03

Calculate the vapor pressure at 50°c of a coolant solution that is 52.0:48.0 ethylene glycol-to-water by volume. at 50.0°c, the density of water is 0.9880 g/ml, and its vapor pressure is 92 torr. the vapor pressure of ethylene glycol is less than 1 torr at 50.0°c.

+3
Answers (1)
  1. 2 September, 17:40
    0
    If we use 100 mL of solution:

    V (ethylene glycol - C ₂H₆O₂) = 0,52 · 100 mL = 52 mL.

    V (water) = 0,48 · 100 mL = 48 mL.

    m (C ₂H₆O₂) = 52 mL · 1,115 g/mL = 57,98 g.

    n (C ₂H₆O₂) = 57,98 g : 62,07 g/mol = 0,934 mol.

    m (H ₂O) = 48 mL · 0,988 g/mL = 47,424 g.

    n (H ₂O) = 45,45 g : 18 g/mol = 2,635 mol.

    mole fraction of solvent: 2,635 mol / (2,635 mol + 0,934 mol) = 0,73.

    Raoult's Law: p (solution) = mole fraction of solvent · p (solvent).

    p (solution) = 0,73 · 92 torr = 67,33 torr.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the vapor pressure at 50°c of a coolant solution that is 52.0:48.0 ethylene glycol-to-water by volume. at 50.0°c, the density of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers