Ask Question
27 July, 10:54

Suppose a reaction mixture, when diluted with water, afforded 300 ml of an aqueous solution of 30 g of the reaction product malononitrile [ch2 (cn) 2], which is to be isolated by extraction with ether. the solubility of malononitrile in ether at room temperature is 20.0 g/100 ml, and in water is 13.3 g/100 ml. what weight of malononitrile would be recovered by extraction with (a) three 100-ml portions of ether and (b) one 300-ml portion of ether? suggestion: for each extraction, let x equal the weight extracted into the ether layer. in part (a), the concentration in the ether layer is x/100 and in the water layer is (30 x) / 300; the ratio of these quantities is equal to k 20/13.3. williamson, kenneth l.; masters, katherine m ... macroscale and microscale organic experiments (available titles coursemate) (page 163). cengage textbook. kindle edition.

+2
Answers (1)
  1. 27 July, 11:19
    0
    A) 1.5 = (x/100mL) ether / [ (30-x) / 300] water

    1.5 = 300x / (3000-100x)

    1.5 (3000-100x) = 300x

    4500-150x = 300x

    4500 = 450x

    X = 10 g (1 portion of 100-mL ether)

    portions of 100-mL ether = 10 g x 3 = 30g malononitrile recovered

    b) 1.5 = (x/300mL) ether / [ (30-x) / 300] water

    1.5 = 300x / (9000 - 300x)

    1.5 (9000 - 300x) = 300x

    13500 - 450x = 300x

    13500 = 750x

    X = 18 g 18 g malononitrile recovered
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose a reaction mixture, when diluted with water, afforded 300 ml of an aqueous solution of 30 g of the reaction product malononitrile ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers