What is the volume occupied by 0.118 mol of helium gas at a pressure of 1.05 atm and a temperature of 322 K?

The volume occupied by 0.118mol of He gas at a pressure of 1.05 atm and temperature of 322k is calculated by use of ideal gas equation

that is PV = nRT

P (Pressure) 1.05 atm

v (volume) = ?

n (number of moles) = 0.118 mol

T (temperature) = 322K

from equation above volume (v) = nRT/p

volume (v) = (0.118 mol x 0.0821 L. atm/k. mol x322k) / 1.05 atm = 2.97 L