0 ml of 0.212 m naoh is neutralized by 13.6 ml of an hcl solution. the molarity of the naoh solution is

I believe the correct volume of 0.212 M NaOH is 25.0 mL and not 0 mL.

Since the reactants are strong base and a strong acid then this is an example of neutralization reaction. The balance chemical reaction is:

NaOH + HCl - - - > NaCl + H2O

We can see from the reaction above that the ratio of NaOH to HCl is 1:1. Therefore,

number of moles HCl = (0.212 mol NaOH / L) * 0.025 L * (1 mol HCl / 1 mol NaOH)

number of moles HCl = 0.0053 mol HCl

Molarity is number of moles divided by volume in Liters, therefore the molarity of HCl solution is:

Molarity HCl = 0.0053 mol HCl / 0.0136 L

Molarity HCl = 0.390 M