How many grams of chlorine gas can be produced from the decomposition of 73.4 g. of aucl3 by this reaction:?

1) first, we have to convert the grams to moles of AuCl3 using the molar mass of the molecule.

molar mass of AuCl3 = 197 + (35.5 x 3) = 303.5 g/mol

73.4 g (1 mol AuCl3 / 303.5 g) = 0.242 moles

2) now. let's convert moles of AuCl3 to moles of chlorine gas (Cl2) using the mole-mole ratio

0.242 mol AuCl3 (3 mol Cl2 / 2 mol AuCl3) = 0.363 mol Cl2

3) finally, we convert moles to grams using the molar mass of Cl2.

molar mass of Cl2 = 35.5 x 2 = 71.0 g/mol

0.363 mol Cl2 (71.0 g / 1 mol) = 25.8 grams