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20 April, 03:14

How many molecules of Cl - are in 410mL solution to. 72 M CaCl2 (aq) ?

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  1. 20 April, 04:47
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    First we calculate the moles of CaCl₂

    moles = concentration (M) x volume (dm³)

    moles = 0.72 x 0.41

    = 0.2952

    Each mole of CaCl₂ releases 2 moles of Cl-

    moles of Cl - = 0.2952 x 2

    = 0.5904

    Each mole contains 6.02 x 10²³ molecules. Total molecules:

    0.5904 x 6.02 x 10²³

    = 3.55 x 10²³ Cl - ions
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