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1 July, 10:38

If 10.0 liters of H2 (g) at stp is heated to a temperature of 546 K what is the new volume

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  1. 1 July, 13:42
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    Answer is: new volume is 19,99 L.

    V₁ (H₂) = 10,0 L.

    T₁ (H₂) = 0°C = 273,15 K.

    T₂ (H₂) = 546 K.

    V₂ (H₂) = ?

    Charles' Law: The Temperature-Volume Law - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:

    V ₁/T₁ = V₂/T₂.

    10,0 L/273,15 K = V ₂/546 K.

    V ₂ = 19,99 L.
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