A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample is saturated with water vapor. if the total pressure of the mixture at 26.4 °c is 749 torr, what is the partial pressure of oxygen? the vapor pressure of water at 26.4 °c is 25.81 mm hg.

In this question, the container has oxygen and water vapor. The container is at 26.4 degrees Celsius temperature and the partial oxygen pressure at 26.4 degrees Celsius is 25.81 torr. Note that torr unit for pressure is equal to 1 mm Hg.

To find the partial pressure of oxygen, you just need to subtract the total pressure with oxygen pressure. The calculation would be:

total pressure = partial oxygen pressure + partial water pressure

749 mm Hg = partial oxygen pressure + 25.81 mmHg

partial oxygen pressure = 749mmHg - 25.81mmHg = 723.19 mmHg