AB Reacts with C2 to yield AC and B.

2AB+C2-->2AC+2B

The molar mass of AB is 75.0 g/mol, the molar mass of AC is 60.0 g/mol, and the molar mass of B is 50.0 g/mol.

a) What is the theoretical yield (in grams) of AC from the reaction of 41.0 g of AB?

b) If the reaction produced 16.5 g of AC, what was the percent yield?

Question A

the theoretical yield of Ac is calculated as follows

calculate the moles of AB = mass/molar mass

=41 g/75 g/mol = 0.55 moles

2AB + C2 = 2AC + 2B

by use of mole ratio between AB : AC which is 2:2 or 1:1 the moles of AC is also 0.55 moles

theoretical mass is therefore = moles x molar mass

= 0.55 x 60 = 33 grams

question B

THe % yield = actual yield/theoretical yield x 100

= 16.5g/33 g x100 = 50% of AC