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19 March, 09:13

A 4.0g sample of iron was heated from 0c to 20c. it absorbed 35.2j of energy as heat. what is the specific heat of this piece of iron

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  1. 19 March, 10:18
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    We are going to use the heat absorbed formula:

    Q = M*C*ΔT

    when Q is the heat absorbed = 35.2 J

    and M is the mass of iron = 4 g

    and C is the specific heat capacity of iron (which we need to calculate)

    ΔT the change in temperature = 20-0 = 20 °C

    so, by substitution:

    35.2 J = 4 g * C * 20°C

    ∴ the specific heat of this piece of iron C = 35.2 / (4g*20°C)

    = 0.44 J/g.°C
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