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15 November, 14:41

For a particular reaction, ΔH = - 99.84 kJ and ΔS = - 16.80 J/K. Calculate ΔG for this reaction at 298 K.

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  1. 15 November, 16:28
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    To solve this given problem, we can use the equation below:

    ΔG=ΔH - T*ΔS

    We are information and values are given and can be used in solving the ΔG of this particular reaction.

    ΔH=-99.84kJ

    ΔS=-16.80 J/K

    T=298K

    ΔG = (-99.84kJ) - (298K*-16.80J/K)

    ΔG=-94.83kJ

    The answer for ΔG is - 94.83kJ.
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