If the design of jewelry requires 0.490 mole of tin, how many grams of tin are needed?

58.2 g For this problem, you simply need to multiply the number of moles of tin you need by the atomic weight of tin. So looking up the atomic weight, you get 118.71 g/mol, so 118.71 g/mol * 0.490 mol = 58.1679 g Rounding the result to 3 significant figures gives you 58,2 g