A solution is made by dissolving 26.42g of (NH4) 2so4 in enough h2o to make 50.00ml of solution

What is the molarity of this solution?

Moles of ammonium sulfate = 26.42/molar mass of (NH4) 2SO4

= 26.42/132.14 = 0.19 mole.

Molarity = moles of ammonium sulfate/volume of solution

= 0.19/50x10^-3

= 3.8M

Molarity = moles of solute/liters of solution

We first need to convert grams of ammonium sulfate to moles.

To convert from grams to moles, we need to divide by it's molecular mass.

26.42 g (NH₄) ₂SO₄ * (1 mole (NH₄) ₂SO₄ / 132.14 g (NH₄) ₂SO₄) = 0.1999 mole (NH₄) ₂SO₄

0.1999 mol/0.05000L = 3.998 M

Since there 4 significant digits in both the volume and mass, we are limited to 4 significant digits.

Your final answer is 3.998 M (NH₄) ₂SO₄.