If 52 J of heat is added to an aluminum can with a mass of 28.4 g, what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.

Q = mass x sph x temp change

temp change = Q / (mass x sph)

Temp change = 57 / (22 x. 903)

Temp Change = 2.97 ∘C

Temp change 3.0 ∘C

We can use the heat equation,

Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (g), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

The given data

Q = 52 J

m = 28.4 g

c = 0.903 J g⁻¹ °C⁻¹

ΔT = ?

By applying the formula,

52 J = 28.4 g x 0.903 J g⁻¹ °C⁻¹ x ΔT

ΔT = 2.03 °C

Hence, the temperature change of aluminium during the heating process is 2.03 °C.