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6 July, 05:53

How many grams of beryllium are needed to produce 36.0 g of hydrogen assume an excess of waater be (s) + 2h2o (l) be (oh) 2 (aq) + h2 (g) ?

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  1. 6 July, 06:13
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    Answer is: 162 g of beryllium.

    Chemical reaction: Be + 2H₂O → Be (OH) ₂ + H₂.

    m (H₂) = 36,0 g.

    m (Be) = ?

    n (H₂) = m (H₂) : M (H₂)

    n (H₂) = 36,0 g : 2 g/mol = 18 mol.

    from reaction: n (Be) : n (H₂) = 1 : 1.

    n (Be) = n (H₂) = 18 mol.

    m (Be) = n (Be) · M (Be).

    n (Be) = 18 mol · 9 g/mol = 162 g.
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