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25 October, 17:07

He henry's law constant of oxygen in water at 25 °c is 773 atm mol-1kg h2o. calculate the molality of oxygen in water under a partial pressure of 0.20 at

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  1. 25 October, 18:26
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    Henry law:

    P = KC

    P = solvent vapour pressure

    K = Henry constant

    C = conc of solute

    So, 0.2 = 773 C

    so, C = 0.2 / 773 = 2.5 x 10^{-4} molal
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