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18 January, 15:57

How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Show all of the work needed to solve this problem.

Zn (s) + 2 HCl (aq) ZnCl2 (aq) + H2 (g)

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  1. 18 January, 18:25
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    The balanced chemical reaction is:

    Zn (s) + 2 HCl (aq) - - - > ZnCl2 (aq) + H2 (g)

    We are given the amount of the hydrochloric acid to be used in the reaction. This will be used for the calculations.

    3.5 mol/L HCl (8.2 L) (1 mol Zn / 2 mol HCl) (65.38 g / 1 mol) = 938.20 g Zn
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