Exactly 500 grams of ice are melted at a temperature of 32°f. (lice = 333 j/g.) calculate the change in entropy (in j/k). (give your answer with three significant figures)

Question

Chemistry

Rachael Contreras

16 September, 06:10

Exactly 500 grams of ice are melted at a temperature of 32°f. (lice = 333 j/g.) calculate the change in entropy (in j/k). (give your answer with three significant figures)

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Tucker Wright · Answer 1

Entropy Change is calculated by (Energy transferred) / (Temperature in kelvin)

deltaS = Q / T

Q = (mass) (latent heat of fusion)

Q = m (hfusion)

Q = (500g) (333J/g) = 166,500J

T (K) = 32 + 273.15 = 305.15K

deltaS = 166,500J / 305.15K

deltaS = 545.63 J/K